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網(wǎng)絡(luò)工程師每日一練試題內(nèi)容(2025/10/21)
試題1
指令寄存器的位數(shù)取決于 ( )。查看答案
試題參考答案:B
試題解析與討論:www.richmond-chase.com/exam/ExamDay.aspx?t1=8&day=2025/10/21
試題2
網(wǎng)絡(luò)生命周期中,五階段周期的缺點(diǎn)是( )。查看答案
試題參考答案:B
試題解析與討論:www.richmond-chase.com/exam/ExamDay.aspx?t1=8&day=2025/10/21
試題3
Network Addrees Translation(NAT) is an Internet standard that enables a local-area network to use one set of IP addresses for internet traffic and another set of ( ) IP addresses for external traffic. The main use of NAT is to limit the number of public IP addresses that an organization or company must use, for both economy and ( ) purposes. NAT remaps an IP address space into another by modifying network address information in the ( ) header of packets while they are in transit across a traffic routing device. It has become an essential tool in conserving global address space in the face of ( ) address exhaustion. When a packet traverses outside the local network, NAT converts the private IP address to a public IP address. If NAT runs out of public addresses,the packets will be dropped and ( )"host unreachable"packets will be sent.查看答案
試題參考答案:C、D、B、A、C
試題解析與討論:www.richmond-chase.com/exam/ExamDay.aspx?t1=8&day=2025/10/21
試題4
關(guān)于網(wǎng)橋和交換機(jī),下面的描述中正確的是( )。查看答案
試題參考答案:C
試題解析與討論:www.richmond-chase.com/exam/ExamDay.aspx?t1=8&day=2025/10/21
試題5
訪問控制列表(ACL)分為標(biāo)準(zhǔn)和擴(kuò)展兩種。下面關(guān)于ACL的描述中,錯(cuò)誤的是 ( ) 。
A、標(biāo)準(zhǔn)ACL可以根據(jù)分組中的IP源地址進(jìn)行過濾
B、擴(kuò)展ACL可以根據(jù)分組中的IP目標(biāo)地址進(jìn)行過濾
C、標(biāo)準(zhǔn)ACL可以根據(jù)分組中的IP目標(biāo)地址進(jìn)行過濾
D、擴(kuò)展ACL可以根據(jù)不同的上層協(xié)議信息進(jìn)行過濾
查看答案
試題參考答案:C
試題解析與討論:www.richmond-chase.com/exam/ExamDay.aspx?t1=8&day=2025/10/21
試題6
在Linux系統(tǒng)中,若要?jiǎng)h除一個(gè)用戶user2及其主目錄,以下命令正確的是( )查看答案
試題參考答案:B
試題解析與討論:www.richmond-chase.com/exam/ExamDay.aspx?t1=8&day=2025/10/21
試題7
某園區(qū)網(wǎng)的用戶無法訪問202.145.12.35,在Windows平臺下, 可以使用()命令判斷故障是否在園區(qū)網(wǎng)內(nèi)部。查看答案
試題參考答案:D
試題解析與討論:www.richmond-chase.com/exam/ExamDay.aspx?t1=8&day=2025/10/21
試題8
路由器出廠時(shí),默認(rèn)的串口封裝協(xié)議是( )。查看答案
試題參考答案:A
試題解析與討論:www.richmond-chase.com/exam/ExamDay.aspx?t1=8&day=2025/10/21
試題9
關(guān)于IEEE 802.3的CSMA/CD協(xié)議,下面結(jié)論中錯(cuò)誤的是 ( ) 。
A、CSMA/CD是一種解決訪問沖突的協(xié)議
B、CSMA/CD協(xié)議適用于所有的802.3以太網(wǎng)
C、在網(wǎng)絡(luò)負(fù)載較小時(shí),CSMA/CD協(xié)議的通信效率很高
D、這種網(wǎng)絡(luò)協(xié)議適合傳輸非實(shí)時(shí)數(shù)據(jù)
查看答案
試題參考答案:B
試題解析與討論:www.richmond-chase.com/exam/ExamDay.aspx?t1=8&day=2025/10/21
試題10
以下關(guān)于報(bào)文摘要(MD5)的描述,正確的是()?查看答案
試題參考答案:C
試題解析與討論:www.richmond-chase.com/exam/ExamDay.aspx?t1=8&day=2025/10/21
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